Chapter 4 Conceptual Project:

Spot the Difference

Consider a function f ⁡ x that is at least twice differentiable. In this project, you will show that the second derivative of f ⁡ x at x = c can be found as the limit of so-called second-order differences, as follows.

f ″ ⁡ c = lim h → 0 ⁡ f ⁡ c + h − 2 ⁢ f ⁡ c + f ⁡ c − h h 2

  1. Instead of working with a secant line through the points c f ⁡ c and c + h f ⁡ c + h like we did when approximating the first derivative, suppose that

    y = a 1 ⁢ x 2 + a 2 ⁢ x + a 3

    is the parabola through the following three points on the graph of f: c − h f ⁡ c − h , c f ⁡ c and c + h f ⁡ c + h . Do you expect to always be able to find coefficients a 1 , a 2 , a 3 ∈ ℝ such that the resulting parabola satisfies the desired conditions? Why or why not? Why would you expect 2 ⁢ a 1 to be "close” to f ″ ⁡ c if h is "small”? What will happen to 2 ⁢ a 1 as h → 0 ? Write a short paragraph answering the above questions.

  2. By substituting the points c − h f ⁡ c − h , c f ⁡ c , and c + h f ⁡ c + h into y = a 1 ⁢ x 2 + a 2 ⁢ x + a 3 , obtain a system of linear equations in unknowns a 1 , a 2 , and a 3 . Solve the system for the unknown a 1 .

  3. Use Questions 1 and 2 to argue that f ″ ⁡ c is the following limit of the second‑order differences.

    f ″ ⁡ c = lim h → 0 ⁡ f ⁡ c + h − 2 ⁢ f ⁡ c + f ⁡ c − h h 2

  4. Use L'Hôpital's Rule to verify the result you found in Question 3.